fix: 修复所有首页板块 pin 滚动不连贯问题
🐛 问题根源: 每个板块有两套独立的 ScrollTrigger 在同一个元素上: - 入场动画用独立的 scrollTrigger - pin 效果用 ScrollTrigger.create 两者互相冲突,导致空白间隙和动画跳变 ✅ 修复方案: 将所有板块的入场动画和 pin 滚动合并为一个统一时间线(timeline), 确保动画从 pin 开始到结束完全连续,无空白区 🔧 修复的 6 个板块: 1. HomeTestimonials - 标题入场 + 卡片逐张切换(淡入淡出) 2. HomeServices - 标题入场 + 卡片飞入归位 + 逐张聚焦 3. HomeAchievements - 逐个成就项展示(前一个淡出,后一个淡入) 4. HomeTechStack - 内容入场 + 标签散开 + 球体旋转 5. HomeProcess - 标题入场 + 线条绘制 + 步骤逐个出现 + 横向滚动 6. HomeUpdates - 标题入场 + 卡片分批出现 🎯 效果: - pin 期间动画完全连续,无空白间隙 - 入场和 pin 共享同一个 timeline - scrub: 0.5 让滚动更平滑 - 每个板块到下一个板块无缝过渡 Co-Authored-By: Claude Opus 4.8 (1M context) <noreply@anthropic.com>
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@@ -206,43 +206,41 @@ onMounted(async () => {
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const cleanupParticles = initParticles()
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ctx = gsap.context(() => {
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// Pin 效果:固定板块,逐个成就项展示
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// 初始状态:全部隐藏
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const totalItems = achievements.length
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const timeline = gsap.timeline()
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// 初始隐藏所有
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achievementElements.value.forEach((item, index) => {
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if (!item) return
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gsap.set(item, { autoAlpha: 0, x: index % 2 === 0 ? -100 : 100 })
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})
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// 逐个展示每个成就项
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for (let i = 0; i < totalItems; i++) {
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timeline.addLabel(`item-${i}`)
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// 统一时间线:逐个展示
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const tl = gsap.timeline()
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timeline.to(achievementElements.value[i], {
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autoAlpha: 1,
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x: 0,
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duration: 0.8,
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ease: 'power3.out',
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for (let i = 0; i < totalItems; i++) {
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// 每个成就项入场,前一个淡出
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if (i > 0) {
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tl.to(achievementElements.value[i - 1], {
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autoAlpha: 0, x: i % 2 === 0 ? 100 : -100,
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duration: 0.5, ease: 'power2.in',
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}, i)
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}
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tl.to(achievementElements.value[i], {
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autoAlpha: 1, x: 0, duration: 0.8, ease: 'power3.out',
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onStart: () => {
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// 触发数字计数
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const numberEl = numberElements.value[i]
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if (numberEl) {
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animateNumber(numberEl, achievements[i].number, achievements[i].suffix)
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}
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if (numberEl) animateNumber(numberEl, achievements[i].number, achievements[i].suffix)
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}
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}, `item-${i}`)
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}, i + 0.2)
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}
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ScrollTrigger.create({
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trigger: rootRef.value,
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start: 'top top',
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end: () => `+=${totalItems * window.innerHeight}`,
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end: () => `+=${(totalItems + 1) * window.innerHeight}`,
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pin: true,
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scrub: true,
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scrub: 0.5,
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anticipatePin: 1,
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animation: timeline,
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animation: tl,
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})
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}, rootRef.value)
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